Answer:
m=3.7 Kg
Explanation:
Given that
F= 50 N
r= 0.12 m
α = 150 rad/s²
The moment of inertia of disk about center
[tex]I=\dfrac{mr^2}{2}[/tex]
I= 0.5 m r²
m=mass  , r=radius
The moment of inertia of disk about O
I' = 0.5 m r²+ m r²
I'=1.5 m r²
The torque produce by force F about O
Ï„ = F x 2r
Ï„ =2 F r
Ï„ = 2 x 50 x 0.12 N.m
Ï„ =12 N.m
We know that
τ = I' α
12 = 1.5 x m x  0.12² x 150
m=3.7 Kg
Mass of the disk m= 3.7 kg
