Answer:Let the amount invested in each be
A and B
A+B=5000
0.1A+0.15B=630
0.1(5000-B)+0.15B=630
500-0.1B+0.15B=630
0.05B=130
B=2600
A=2400
Step-by-step explanation:
There are 2400 invested in 10% and 2800 invested in 15%.
Given
A total of 5000 is invested part at 10% and the remainder at 15%.
Total invested amount invested 5000.
[tex]\rm x+y=5000[/tex]
A total of 5000 is invested part at 10% and the remainder at 15%.
[tex]\rm 0.10x +0 .15y = 630[/tex]
On solving both the equations
From equation 1
[tex]\rm x+y=5000\\\\y=5000-x[/tex]
Substitute the value of y in equation 2
[tex]\rm 0.10x +0 .15(5000 -x) = 630\\\\0.10x+750-0.15x=630\\\\-0.5x=630-750\\\\-0.05x=-120\\\\x=\dfrac{-120}{-0.05}\\\\x=2400[/tex]
Substitute the value of x in equation 1
[tex]\rm x+y=5000\\\\ 2400+y=5000\\\\y=5000-2400\\\\y=2600[/tex]
Hence, there are 2400 invested in 10% and 2800 invested in 15%.
To know more about the System of equations click the link given below.
https://brainly.com/question/494802
