Answer:
Explanation:
Given
Current is flowing towards right side
Considering right side i.e. +x to be positive and direction outside the paper be +k
suppose charge is below the wire and is moving towards right
[tex]v=v_0\hat{i}[/tex]
magnetic field below the wire is outside the Paper using right hand thumb rule
[tex]B=B_0\hat{k}[/tex]
[tex]F=q(\vec{v}\times \vec{B})[/tex]
[tex]F=q(v_0\hat{i}\times B_0\hat{k})[/tex]
[tex]F=-qv_0B_0\hat{j}[/tex]
i.e. Force acts in Downward direction
i charge is moving towards left i.e.
[tex]v=-v_0\hat{i}[/tex]
[tex]F=q(-v_0\hat{i}\times B_0\hat{k})[/tex]
[tex]F=qv_0B_0\hat{j}[/tex] towards upward direction
