Respuesta :
Answer:
s= 544 m Ā ā =39Ā°
Explanation:
Initial velocity= Vi = 64 m/s
projection angle=ā =60Ā°
Horizontal velocity= Vx =Vicosā
Vx= 64Cos(60Ā°)
Vx=32 m/s
Horizontal distance covered in 6 sec:
Sx= Vx*t Ā Ā (horizontal velocity remain constant)
Sx= Ā 32*6 =192 m
Vertical Velocity= Vy = Vi*Sinā
Vy= 64 * Sin(60Ā°)
Vy=55.43 m/s
Vertical distance covered:
Sy= Vy * t +1/2 a*t^2 Ā Ā Ā (here a=-g)
Sy= 55.43*6 -1/2(9.8*6^2)
Sy= 156.2 m
Total displacement from starting point is:
s=[tex]\sqrt{(Sx)^{2}+(Sy)^{2} Ā }[/tex]
s=[tex]\sqrt{(192)^{2}+(156.2)^{2} Ā }[/tex]
s= 247.5 m ā 39Ā°
