• A kid on a bike is at the top of a hill, at
rest. His KE = 0 J and GPE = 2500 J. He
rides down the hill and launches of a
ramp. During the jump, in the air, his GPE
= 1200 J. What is his KE at this time?

According to the law of conservation of energy, the total mechanical energy (potential+kinetic) of the bike must be conserved at any point of the motion.

Therefore, we can write:

[tex]KE_i + GPE_i = KE_f + GPE_f[/tex]

where:

[tex]KE_i = 0 J[/tex] is the initial kinetic energy of the bike, at the top

[tex]GPE_i = 2500 J[/tex] is the initial potential energy, at the top

[tex]KE_f[/tex] is the final kinetic energy

[tex]GPE_f = 1200 J[/tex] is the final potential energy

Solving for [tex]KE_f[/tex], we find the final kinetic energy:

[tex]KE_f = KE_i + GPE_i - GPE_f = 0+2500 -1200 = 1300 J[/tex]

Learn more about kinetic and potential energy:

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• A kid on a bike is at the top of a hill, at rest. His KE = 0 J and GPE = 2500 J. He rides down the hill and launches of a ramp. During the jump, in the air, his GPE = 1200 J. What is his KE at this time?

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• A kid on a bike is at the top of a hill, at
rest. His KE = 0 J and GPE = 2500 J. He
rides down the hill and launches of a
ramp. During the jump, in the air, his GPE
= 1200 J. What is his KE at this time?