Answer:
23 mi
Explanation:
Let us first record all the values we have
acceleration = 4 ft/s
max speed = 90 mi/hr * 1 hr/3600s * 5280 ft/1 mi = 132 ft/s
We can use the equation of linear motion since acceleration is constant
distance covered = distance during acceleration + distance during costant
velocity
[tex]s = \frac{v_{f} ^{2} - v_{i} ^{2} }{2a} + v_{i}t\\\\s = \frac{132 ^{2} - 0^{2} }{2*4} + 132*900\\s = 120 978ft[/tex]
distance in miles = 120 978 ft * 1 mi/5280 ft = 22.9125 mi ≈ 23 mi
