Answer:
(-4,8) is the solution set for given question.
Step-by-step explanation:
Given that:
Y=2x+16 ---------- eq1
2x-7y=-64 -------- eq2
Rearranging eq1:
-2x + y = 16 ---------- eq3
By adding eq2 and eq3:
-6y = -48
Dividing both sides by -6:
y = 8
Putting value of in eq1 we get:
8 = 2x + 16
By simplifying:
subtracting 16 from both sides:
8-16 = 2x
-8 = 2x
Dividing both sides by 2 we get:
x = -4
So the solution set for given system will be: (-4, 8)
i hope it will help you!
