A satellite dish is in the shape of a parabolic surface. Signals coming from a satellite strike the surface of the dish and are reflected to the​ focus, where the receiver is located. The satellite dish has a diameter of 14 feet and a depth of 2 feet. How far from the base of the dish should the receiver be​ placed?

Respuesta :

Answer: 6.125 ft

Explanation:

If this dish has the form of a concave upward parabola and its vertex [tex]p[/tex] is at the origin, its corresponding equation is:

[tex]x^{2}=4py[/tex]

Where:

[tex]x[/tex] is the radius, which can be found by dividing the diameter [tex]d=14 ft[/tex] by half. Hence [tex]x=\frac{d}{2}=\frac{14 ft}{2}=7 ft[/tex]

[tex]y=2 ft[/tex] is the depth

[tex]p[/tex] is the vertex of the parabola, where its base is

Finding [tex]p[/tex]:

[tex]p=\frac{x^{2}}{4y}[/tex]

[tex]p=\frac{(7 ft)^{2}}{4(2 ft)}[/tex]

Finally:

[tex]p=6.125 ft[/tex] This is where the the receiver should be placed

Answer:

6

(0, 3)

Explanation:

on edge

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