Answer:
[tex]\boldmath-5-2i\sqrt{\boldmath11}[/tex]
Step-by-step explanation:
The not simplified form is [tex]-5-\sqrt{-44}[/tex]
you know that [tex]\sqrt{a\times b} = \sqrt{a} \times\sqrt{b}[/tex] is true a and b are both positive or one of it is negative (not both of them).
You can write -44 as -1 × 4 × 11 inside square root.
So, [tex]\sqrt{-44} = \sqrt{-1\times4\times11}=\sqrt{-1}\times\sqrt{4}\times\sqrt{11}=i\times2\times\sqrt{11}[/tex] ([tex]\sqrt{4}=2[/tex])
[tex]\therefore -5-\sqrt{-44} = -5-2i\sqrt{11}[/tex]
(NOTE : You must know that [tex]\boldmath\sqrt{\boldmath-1}[/tex] is written as [tex]\boldsymbol i[/tex] )
