The new acceleration is [tex]108 m/s^2[/tex]
Explanation:
We can answer this problem by applying Newton's second law, which states that:
[tex]F=ma[/tex]
where
F is the net force on an object
m is the mass of the object
a is its acceleration
The equation can be rewritten as
[tex]a=\frac{F}{m}[/tex]
In this problem, the initial acceleration is
[tex]a=18.0 m/s^2[/tex]
Later:
- The net force is tripled: [tex]F'=3F[/tex]
- The mass is halved: [tex]m'=\frac{m}{2}[/tex]
Therefore, the new acceleration is:
[tex]a'=\frac{F'}{m'}=\frac{3F}{m/2}=6\frac{F}{m}=6a[/tex]
which means that the new acceleration is 6 times the original acceleration, therefore
[tex]a'=6(18)=108 m/s^2[/tex]
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