The minimum length of the runway must be 300 m
Explanation:
The motion of the airplane is a uniformly accelerated motion (=constant acceleration), therefore we can solve the problem by applying the following suvat equation:
[tex]s=(\frac{u+v}{2})t[/tex]
where
v is the final velocity of the plane
u is the initial velocity
t is the time interval
s is the distance covered
For the plane in this problem, we have:
u = 4 m/s (initial velocity)
v = 30 m/s (final velocity)
t = 15 s (time interval)
Solving for s, we find the distance covered by the plane during its acceleration:
[tex]s=(\frac{4+30}{2})(15)=255 m[/tex]
Therefore, the minimum length of the runway must be 300 m.
Learn more about accelerated motion:
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