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A woman with a mass of 55 kg stands erect on a level ground. What is the approximate magnitude and direction of vertical ground reaction force Fz applied by the person’s weight? The direction of the woman’s weight vector is defined as being negative

Respuesta :

Answer:

[tex]F_z=539\ N[/tex]

Explanation:

Given that,

Mass of the woman, m = 55 kg

Let [tex]F_z[/tex] is the reaction force that is applied by the person’s weight. It is given by :

[tex]F_z=mg[/tex]

g is the acceleration due to gravity

[tex]F_z=55\ kg\times 9.8\ m/s^2[/tex]

[tex]F_z=539\ N[/tex]

So, the magnitude of vertical ground reaction force due to the person's weight is 539 N. Hence, this is the required solution.

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