To solve this problem it is necessary to apply the concepts related to the Flow Rate. It is understood as the volumetric amount transported during a certain time and can be calculated as
[tex]Q = AV[/tex]
Where
A = Area
V = Velocity
Our values are given as
[tex]r = 5.27*10^{-3}m \rightarrow A = \pi r^2 = \pi ( 5.27*10^{-3})^2 = 8.72*10^{-5}m^2[/tex]
[tex]Q = 0.401*10^{-3}m^3/s[/tex]
Replacing and rearranging to find the velocity
[tex]V = \frac{Q}{A}[/tex]
[tex]V = \frac{0.401*10^{-3}}{8.72*10^{-5}}[/tex]
[tex]V= 4.59m/s[/tex]
Therefore the speed of the water at the end of the Nozzle is 4.59m/s
