Answer
given,
mass of baseball(m) = 144 g = 0.144 Kg
initial velocity(u) = 29 m/s
mass of brick(M) = 5.25 Kg
speed of the brick (v') = 1.32
speed of base ball after collision = ?
using conservation of momentum
m u = m v + Mv'
0.144 x 29 = 0.144 v + 5.25 x 1.32
0.144 v = -2.754
v = -19.125 m/s
b) KE before collision
[tex]KE = \dfrac{1}{2}mv^2[/tex]
[tex]KE = \dfrac{1}{2}\times 0.144 \times 29^2[/tex]
KE_i = 60.55 J
KE after collision
[tex]KE = \dfrac{1}{2}mv^2 +\dfrac{1}{2}Mv'^2[/tex]
[tex]KE = \dfrac{1}{2}\times 0.144\times 19.125^2 +\dfrac{1}{2}\times 5.25\times 1.32^2 [/tex]
KE_f = 30.91 J
