Explanation:
It is given that,
weight of the shot- putter, W = 71.1 kg
Initial position, [tex]x_i=1.52\ m[/tex]
Final position, [tex]x_f=2.13\ m[/tex]
To find,
Work done and the change in potential energy.
Solution,
(a) Let W is the work done by the gravitational force when the shot has risen to a height of 2.13 m above the ground. It is given by :
[tex]W_f=F\times x_f[/tex]
[tex]W_f=71.1\times 2.13[/tex]
[tex]W_f=151.44\ J[/tex]
(b) We know that the potential energy is equal to the work done by an object such that,
[tex]\Delta P=P_f-P_i[/tex]
[tex]\Delta P=W_f-W_i[/tex]
[tex]\Delta P=151.44-71.1\times 1.52[/tex]
[tex]\Delta P=43.36\ J[/tex]
