The voltage in the secondary coil is 20 V
Explanation:
The transformer equation gives the relationship between the voltage in the primary and secondary coil of a transformer:
[tex]\frac{V_p}{N_p}=\frac{V_s}{N_s}[/tex]
where
[tex]V_p[/tex] is the voltage in the primary coil
[tex]V_s[/tex] is the voltage in the secondary coil
[tex]N_p[/tex] is the number of turns in the primary coil
[tex]N_s[/tex] is the number of turns in the secondary coil
It can also be rewritten as
[tex]\frac{V_s}{V_p}=\frac{N_s}{N_p}[/tex]
In this problem, we have a step-up voltage that doubles the voltage, so:
[tex]\frac{V_s}{V_p}=2[/tex]
The voltage in the primary coil is 10 V,
[tex]V_p = 10 V[/tex]
Therefore, the voltage in the secondary coil is
[tex]V_s = 2V_p = 2(10)=20 V[/tex]
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