Answer:
The hydrogen ion concentration is [tex]3.6 \times 10^{-13}M[/tex].
Explanation:
From the given,
Volume of NaOH = 500 ml = 0.500L
Moarity of NaOH = 0.156M
The number of moles of NaOH is calculated is a follows.
[tex]M=\frac{n}{V}[/tex]
Substitute the given values.
[tex]0.156M =\frac{n}{0.500L}[/tex]
[tex]n=0.078\,mole[/tex]
Volume of [tex]CH_{3}COOH[/tex] = 500 ml = 0.500L
Moarity of [tex]CH_{3}COOH[/tex] = 0.100M
The number of moles of [tex]CH_{3}COOH[/tex] is calculated is a follows.
[tex]M=\frac{n}{V}[/tex]
Substitute the given values.
[tex]0.100M =\frac{n}{0.500L}[/tex]
[tex]n=0.05\,mole[/tex]
NaOH is a strong electrolyte
The number of moles NaOH left in the solution is
[tex]0.078 mol- 0.05=0.028\,mol[/tex]
Therefore, hydroxide ion concentration is 0.028 mol
The hydrogen concentration
[tex][H^{+}][OH^{-}]=10^{-14}[/tex]
[tex][H^{+}]= \frac {10^{-14}}{[OH^{-}]}[/tex]
[tex][H^{+}]= \frac {10^{-14}}{0.028}=3.6 \times 10^{-14}[/tex]
Therefore, hydrogen ion concentration is [tex]3.6 \times 10^{-14}[/tex],
