Two forces act on a 42-kg object. One force has magnitude 65 N directed 59° clockwise from the positive x-axis, and the other has a magnitude 35 N at 32° clockwise from the positive y-axis. What is the magnitude of this object's acceleration?

Respuesta :

Answer:

a =  1.39 m/s²

Explanation:

given,

mass of object = 42 Kg

Force₁ = 65 N directed 59° clockwise from the positive x-axis

Force₂ = 35 N  32° clockwise from the positive y-axis

F_x = 65 cos 59° + 35 sin 32°

F_x = 33.48 + 18.55

F_x = 52.024 N

F_y = -65 sin 59° + 35 cos 32°

F_y = -55.72 + 29.68

F_y = -26.04 N

[tex]F = \sqrt{F_x^2 + F_y^2}[/tex]

[tex]F = \sqrt{52.04^2 + -26.04^2}[/tex]

F = 58.19 N

F = ma

58.19  = 42 x a

a =  1.39 m/s²

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