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1. How many molecules are present in 3 moles of silicon dioxide (sio2)
A. 5.00 x 10^23
B. 6.02 x 10^23
C. 12.36 x 10^23
D. 18.06 x 10^23

2. What is the molar mass of Ag2S?

3. In the balanced equation 4KO + 2CO2 = 2K2CO3 +CO3 Which two chemicals have a molar ratio of 3:4?

Respuesta :

Neetoo

Answer:

Explanation:

1. How many molecules are present in 3 moles of silicon dioxide (sio2)

A. 5.00 x 10^23

B. 6.02 x 10^23

C. 12.36 x 10^23

D. 18.06 x 10^23

Answer:

18.066  × 10²³atoms

Explanation:

Given data:

Moles of silicon dioxide = 3 mol

Number of molecules = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

one mole = 6.022 × 10²³  atoms

3 mole × 6.022 × 10²³ atoms / 1mol

18.066  × 10²³atoms

2. What is the molar mass of Ag2S?

Answer:

Molar mass of  Ag₂S = 247.8014 g/mol

Explanation:

The molar mass of a chemical compound is sum of atomic mass of all constituent atoms.

For Ag₂S

Atomic mass of Ag = 107.8682 amu

Atomic mass of S = 32.065 amu

There are two silver atoms that's why

107.8682 amu × 2= 215.7364

Molar mass of Ag₂S:

Molar mass of  Ag₂S =  215.7364 + 32.065

Molar mass of  Ag₂S = 247.8014 g/mol

3) In the balanced equation 4KO + 2CO2 = 2K2CO3 + CO3 Which two chemicals have a molar ratio of 3:4?

Answer:

The equation:

4KO₂ + 2CO₂  → 2K₂CO₃ + 3O₂

In this balanced equation oxygen and potassium superoxide have ration 3:4.

Explanation:

Chemical equation:

4KO + 2CO₂  → 2K₂CO₃ + CO₃

The given equation does not have any two chemical ration 3:4.

The equation:

4KO₂ + 2CO₂  → 2K₂CO₃ + 3O₂

In this balanced equation oxygen and potassium superoxide have ration 3:4.

Coefficient with reactant and product.

Reactant                             Product

KO₂ = 4                             K₂CO₃ = 2

CO₂  = 2                            O₂ = 3

So KO₂ and oxygen have molar ratio 3 : 4 in balanced chemical equation.

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