Answer:
20.02 N
Explanation:
The force the spring exerts is given by a law called Hooke's law
[tex]F=kx[/tex]
where
k = Spring constant
x = Displacement
[tex]k_l[/tex] = 34 N/m
[tex]k_r[/tex] = 57 N/m
Here the block is pulled 0.22 to the left so it will also move 0.22 m to the right
So, the total force is given by
[tex]F=k_lx+k_rx\\\Rightarrow F=34\times 0.22+57\times 0.22\\\Rightarrow F=20.02\ N[/tex]
The magnitude of the net force on the block is 20.02 N
