Respuesta :
Answer:
There will be produced 0.01 moles of CO2
Explanation:
Step 1: Data given
volume of 0.20 M KMnO4 solution = 20 mL = 0.02 L
Volume of 0.10 M Na2C2O4 solution = 50 mL = 0.05 L
Step 2: The balanced equation
2 MnO4-(aq) + 5C2O4^2- (aq) + 16 H+ (aq) → 2 Mn^2+ (aq) + 10CO2 (g) + 8H2O (l)
Step 3: Calculate moles of KMnO4
moles KMnO4 = Molarity * volume
moles KMnO4 = 0.20 M * 0.02 L
moles KmnO4 = 0.004 moles
Step 4: Calculate moles of Na2C2O4
Moles Na2C2O4 = 0.10 M * 0.05 L
Moles Na2C2O4 = 0.005 moles
Step 5: Calculate limiting reactant
For 2 moles KMnO4 we need 5 moles Na2C2O4
Na2C2O4 is the limiting reactant
There will react 0.005 moles
KMnO4 is in excess. There will react 0.005 / 2.5 = 0.002 moles
Step 6: Calculate moles of CO2
For 2 moles KMnO4 we need 5 moles Na2C2O4, there will be produced 10 moles of CO2
For 0.005 moles of Na2C2O4 there will be produced 0.01 moles of CO2
There will be produced 0.01 moles of CO2
