The velocity of the ping-pong ball must be 2547 m/s
Explanation:
The momentum of an object is given by:
[tex]p=mv[/tex]
where
m is the mass of the object
v is its velocity
For the bowling ball in this problem,
m = 5.73 kg
v = 1.6 m/s
So its momentum is
[tex]p=(5.73)(1.6)=9.17 kg m/s[/tex]
Now we want the ping-pong ball to have the same momentum:
[tex]p'=9.17 kg m/s[/tex]
The mass of the ping-pong ball is
[tex]m'=3.6 g = 0.0036 kg[/tex]
Therefore, its velocity must be
[tex]v'=\frac{p'}{m'}=\frac{9.17}{0.0036}=2547 m/s[/tex]
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