Answer:
The force of static friction acting on the luggage is, Fₓ = 180.32 N
Explanation:
Given data,
The mass of the luggage, m = 23 kg
You pulled the luggage with a force of, F = 77 N
The coefficient of static friction of luggage and floor, μₓ = 0.8
The formula for static frictional force is,
Fₓ = μₓ · η
Where,
η - normal force acting on the luggage 'mg'
Substituting the values in the above equation,
Fₓ = 0.8 x 23 x 9.8
= 180.32 N
Hence, the minimum force require to pull the luggage is, Fₓ = 180.32 N
Answer:
184N
Explanation:
Frictional force is defined as a force of opposition. This force opposes the moving force. The body placed on a plane surface has a frictional force proportional to the normal reaction force acting on the body.
Mathematically, Ff = nR where;
Ff is the frictional force
n is the coefficient of static friction between the luggage and the floor.
R is the normal reaction which is equal to the weight (W) of the body.
W = mg
Weight = 23×10 = 230N
Since weight = normal reaction
Normal reaction = 230N
coefficient of friction between the luggage and the floor = 0.8
Frictional force (Ff) = 0.8×230
Frictional force = 184N
Therefore, the force of static friction acting on the luggage is 184N
