Answer:
[tex]1)\ z=120\\\\2)\ g=46\\\\3)\ d=108\\\\4)\ r=39[/tex]
Step-by-step explanation:
1) Given the equation:
[tex]z\div12=10[/tex]
You can rewrite it in the following form:
[tex]\frac{z}{12}=10[/tex]
You must solve for "z". To do it, you can multiply both sides of the equation by 12.
Then you get this solution:
[tex](12)(\frac{z}{12})=(10)(12)\\\\z=120[/tex]
2) The equation given is:
[tex]5g=230[/tex]
Now, in order to solve for the variable "g", you can divide both sides of the equation by 5.
Then you get the following result:
[tex]\frac{5g}{5}=\frac{230}{5}\\\\g=46[/tex]
3) Given the equation:
[tex]d-21=87[/tex]
You can solve for "d" adding 21 to both sides of the equation.
So the value of "d" is:
[tex]d-21+21=87+21\\\\d=108[/tex]
4) Having this equation:
[tex]r + 35 = 74[/tex]
You must subtract 35 from both sides of the equation in order to find the value of the variable "r".
This is:
[tex]r + 35-35 = 74-35\\\\r=39[/tex]
