Answer:
Steven is 15 and one half years old now
Step-by-step explanation:
Linear equations
Sometimes we need to know the value of a variable in a given equation and that variable is given as a polynomial of degree 1. Solving for that variable means isolating it and replacing the other known values
Steven was 7 years old eight and one-half years ago. If we call x as the actual age of Steven, his age eight and one-half years ago was
[tex]x-8\frac{1}{2}[/tex]
We know he was 7 years old then, so
[tex]x-8\frac{1}{2}=7[/tex]
We need to know his actual age, so let's solve for x, adding [tex]8\frac{1}{2}[/tex] to each side of the equation
[tex]x-8\frac{1}{2}+8\frac{1}{2}=7+8\frac{1}{2}[/tex]
Simplifying
[tex]x=15\frac{1}{2}[/tex]
Steven is 15 and one half years old now