Answer:
The balanced half-reaction in which sulfate ion is reduced to sulfite ion is a two electron process
Explanation:
In the sulfate anion, S, acts with +6 in the oxidation number
SO₄⁻²
This is the anion from the sulfuric acid, when it lost the 2 protons
H₂SO₄ → 2H⁺ + SO₄⁻²
In the sulfite anion, S, acts with +4 in the oxidation number.
SO₃⁻²
This is the anion, generated when the sulfurose acid lost the 2 protons.
H₂SO₃ → SO₃⁻² + 2H⁺
In acidic medium
2H⁺ + SO₄⁻² + 2e⁻ → SO₃⁻² + H₂O
In basic medium
H₂O + SO₄⁻² + 2e⁻ → SO₃⁻² + 2OH⁻
The balanced half-reaction in which sulfate ion is reduced to sulfite ion is a two-electron process.
Half-reactions are reactions that make use of electrons, and are usually first balanced by an atom.
The balance is to allow for the replacement of the number of electrons lost to equal to the number of electrons gained.
In the sulfite anion, S, acts with +4 in the oxidation number.
H₂SO₃ → SO₃⁻² + 2H⁺
SO₃⁻² is the anion, generated when the sulfurose acid lost the 2 protons
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