To answer this question is necessary to apply the concepts related to Bernoulli's equation. The Bernoulli-related concept describes the behavior of a liquid moving along a streamline. Pressure can be defined as the proportional ratio between height, density and gravity:
[tex]P = h\rho g[/tex]
Where,
h = Height
[tex]\rho[/tex] = Density
g = Gravity
Our values are
[tex]\rho = 1000kg/m^3 \rightarow[/tex] density of water at normal conditions
h = 7.3m
[tex]g = 9.8m/s^2[/tex]
PART A) Replacing these values to find the total pressure difference we have to
[tex]P_1 = h_1 \rho g[/tex]
[tex]P_1 = (7.3)(1000)(9.8)[/tex]
[tex]P_1 = 71540Pa[/tex]
In this way the pressure change would be subject to
[tex]\Delta = P_2-P_1[/tex]
[tex]\Delta = 2.1*10^5Pa- 0.7154*10^5Pa[/tex]
[tex]\Delta = 138460Pa[/tex]
[tex]\Delta = 0.135Mpa[/tex]
PART B) Considering the pressure gauge of the group as the ideal so that at a height H the water cannot flow even if it is open we have to,
[tex]P_2 = H\rho g[/tex]
[tex]2.1*10^5 = H (1000)(9.8)[/tex]
[tex]H = 21.42m[/tex]
Therefore the high which could a faucet be before no water would flow from it is 21.42m
