Write an inequality to represent the graph.

a solid line passing through points 0 comma 2 and 4 comma negative 1 with shading below the line

y is greater than or equal to negative four thirds times x plus 2
y is less than or equal to negative three fourths times x plus 2
y is greater than or equal to negative three fourths times x plus 2
y is less than or equal to negative four thirds times x plus 2

Respuesta :

Answer:

[tex]y \leq -\frac{3}{4}x+2[/tex]

y is less than or equal to negative three fourths times x plus 2

Step-by-step explanation:

step 1

Find the slope of the solid line

we have the ordered pairs

(0,2) and (4,-1)

Find the slope m

[tex]m=(-1-2)/(4-0)[/tex]

[tex]m=-\frac{3}{4}[/tex]

step 2

Find the linear equation of the solid line in slope intercept form

[tex]y=mx+b[/tex]

we have

[tex]m=-\frac{3}{4}[/tex]

[tex]b=2[/tex] ---> the y-intercept is given

substitute

[tex]y=-\frac{3}{4}x+2[/tex]

step 3

Find the inequality

Remember that the solution is the shaded area below the solid line

therefore

The inequality is

[tex]y \leq -\frac{3}{4}x+2[/tex]

y is less than or equal to negative three fourths times x plus 2

Answer:

y is less than or equal to negative three fourths times x plus 2 or B

Step-by-step explanation:

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