Respuesta :
The change in internal energy is "1.4 kJ".
According to the question,
Volume,
- V₁ = 2 L
- V₂ = 5 L
Pressure,
- P = 2 atm
Change is volume,
ΔV = [tex]V_2-V_1[/tex]
= [tex]5-2[/tex]
= [tex]3 \ L[/tex]
As we know,
→ [tex]Work = -Pd V[/tex]
[tex]= -2(3)[/tex]
[tex]= -6\times 101.325[/tex]
[tex]= -0.6 \ J[/tex]
Now,
→ [tex]U = 2-0.6[/tex]
[tex]= 1.39 \ kJ[/tex]
Thus the answer above i.e., "choice A" is correct.
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