Answer:
0.800 moles of[tex]CO_2[/tex] will be produced when 0.400 moles of [tex]C_6H_1_2O_6[/tex] react and are decomposed
Explanation:
The decomposition of [tex]C_6H_1_2O_6[/te can be written as
[tex]C_6H_1_2O_6[/tex] (aq) ------> 2C2H5OH (aq) + 2CO2
¬moles of [tex]C_6H_1_2O_6[/tex] = 0.400 moles
Moles of [tex]CO_2[/tex] produced will be calculated by the formula,
Moles of CO2 = 0.400 moles of [tex]C_6H_1_2O_6[/tex] [tex]\left(\frac{2 \text { moles of } \mathrm{CO}_{2}}{1 \text { mole of } C_{6} \mathrm{H}_{12} \mathrm{O}_{6}}\right)[/tex]
Substituting the values,
Moles of [tex]CO_2[/tex] = [tex]\frac{0.400 \times 2}{1}[/tex] = 0.400*2 = 0.800 moles
Therefore, 0.800 moles of[tex]CO_2[/tex] will be produced when 0.400 moles of [tex]C_6H_1_2O_6[/tex] react and are decomposed
