contestada

If the absolute refractive index of water is 1.33) then the time taken by light to move
a distance (20 min water equals (The speed of light in air = 3 x 10 m/s)​

Respuesta :

Light takes 8.9 ns to cover 20 m in water

Explanation:

The index of refraction of a medium is equal to the ratio between the speed of light in a vacuum and the speed of light in the medium:

[tex]n=\frac{c}{v}[/tex]

where

[tex]c=3\cdot 10^8 m/s[/tex] is the speed of light in a vacuum

v is the speed of light in the medium

For water,

[tex]n=1.33[/tex]

So the speed of light in water is

[tex]v=\frac{c}{n}=\frac{3\cdot 10^8}{1.33}=2.25\cdot 10^8 m/s[/tex]

Therefore, the  distance covered by light in water in a time interval t is

[tex]d=vt[/tex]

Here we want to know the time taken for light to cover a distance of

d = 20 m

Solving the equation for t, we find

[tex]t=\frac{d}{v}=\frac{20}{2.25\cdot 10^8}=8.9\cdot 10^{-8} s = 89 ns[/tex]

Learn more about refraction here:

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