Respuesta :
Answer: The standard reduction potential for reduction half reaction is 1.82 V
Explanation:
The given chemical reaction follows:
[tex]2Co^{3+}(aq.)+2Cl^(aq.)\rightarrow 2Co^{2+}(aq.)+Cl_2(g)[/tex]
Oxidation half reaction: [tex]2Cl^-\rightarrow Cl_2+2e^-[/tex]
Reduction half reaction: [tex]Co^{3+}+e^-\rightarrow Co^{2+}[/tex]
Substance getting oxidized always act as anode and the one getting reduced always act as cathode.
To calculate the [tex]E^o_{cell}[/tex] of the reaction, we use the equation:
[tex]E^o_{cell}=E^o_{cathode}-E^o_{anode}[/tex]
We are given:
[tex]E^o_{Cl_2/2Cl^-}=1.36V\\\\E^o_{cell}=0.46V[/tex]
Putting values in above equation, we get:
[tex]0.46=E^o_{Co^{3+}/Co^{2+}}-1.36\\\\E^o_{Co^{3+}/Co^{2+}}=(0.46+1.36)V=1.82V[/tex]
Hence, the standard reduction potential for reduction half reaction is 1.82 V
