Answer:
Explanation:
given,
mass of wagon = 20 Kg
horizontal acceleration = 0.5 m/s²
force of pull = 120 N
angle with horizontal = 25°
Applying newtons second law
F cos θ - f = m a
f = F cos θ- ma
f = 120 cos 25° - 20 x 0.5
f = 99 N
we know,
f = μ N
μ =[tex]\dfrac{f}{N}[/tex]
μ =[tex]\dfrac{99}{mg - Fsin \theta}[/tex]
μ =[tex]\dfrac{99}{20\times 9.8 - 120 sin 25^0}[/tex]
μ = 0.68
