The partition coefficient for caffeine between dichloromethane and water is 4.6. Assume that your 100 mL tea solution (in water) contained 0.10 g of caffeine. What is your theoretical yield of caffeine if: You extract with only one 15 mL portion of CH2Cl2?

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Answer:

Theoretical yield is 0,041g of caffeine

Explanation:

The partition coefficient formula is:

[tex]k = \frac{CaffeineDichloromethane}{CaffeineWater}[/tex]

Where k is partition coefficient (4,6)

The Caffeine in water at equilibrium will have a concentration of:

(0,10g-x) / 100mL

And Caffeine in dichloromethane will be:

xg / 15mL -Where x grams are the theoretical yield of caffeine-

Replacing:

[tex]4,6 = \frac{X/15}{(0,10g-X)/100}[/tex]

[tex]4,6 = \frac{100X}{15(0,10g-X)}[/tex]

[tex]4,6 = \frac{100X}{1,5-15X}[/tex]

6,9 - 69X = 100X

6,9 = 169X

0,041 g = X

I hope it helps!

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