Respuesta :
The one which one will be hitting ground first will be projectile launched at angle 30°.
Explanation:
A projectile fired will be having two velocities horizontal velocity and vertical velocity.
If u is the velocity of firing
Horizontal velocity = u cosθ
Vertical velocity = u sinθ
Consider vertical motion of projectile, we have equation of motion
v = u + at
At maximum height
Final velocity, v = 0 m/s
Acceleration, a = -g = -9.81 m/s²
Initial velocity, u = u sinθ
0 = u sinθ - 9.81 x t
[tex]t=\frac{usin\theta }{9.81}[/tex]
Time of flight of projectile = 2 x t
[tex]\texttt{Time of flight of projectile =}2\times \frac{usin\theta }{9.81}[/tex]
Here for both projectiles initial velocity is same, time depends upon angle of projection.
sin 30 = 0.5
sin 60 = 0.866
So, maximum time is for the projectile which is projected at 60 degrees.
The one which one will be hitting ground first will be projectile launched at angle 30°.
