Answer:
[tex]\large\boxed{(f\cdot g)(x)=-16x^3+10x^2-14x}[/tex]
Step-by-step explanation:
[tex]f(x)=-2x\\\\g(x)=8x^2-5x+7\\\\(f\cdot g)(x)=f(x)\cdot g(x)\\\\\text{substitute:}\\\\(f\cdot g)(x)=(-2x)(8x^2-5x+7)\qquad\text{use the distributive property}\\\\(f\cdot g)(x)=(-2x)(8x^2)+(-2x)(-5x)+(-2x)(7)\\\\(f\cdot g)(x)=-16x^3+10x^2-14x[/tex]