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Hello....I need help with this question.

If the velocity of a moving car increases from 9.0 m/s to 25.0 m/s in the span of 5 seconds, what is the average acceleration during this time period, in m/s2

Respuesta :

Answer:

3.2 m/s²

Explanation:

Acceleration can be calculated as:

v = u + at (where v is final velocity, u is initial velocity, a is acceleration and t is time)

25 m/s  = 9 m/s  + a(5 s)  (a is unknown)

16 m/s  = a(5 s)

a = 3.2 m/s²

We assume that this is a uniform acceleration (meaning that the velocity increases at an equal rate for those 5 seconds).

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