A basketball team sells tickets that cost​ $10, $20,​ or, for VIP​ seats,​ $30. The team has sold 3237 tickets overall. It has sold 145 more​ $20 tickets than​ $10 tickets. The total sales are ​$62030. How many tickets of each kind have been​ sold?

Respuesta :

jthao6

Answer: $10 = 1,546 tickets sold

$20 = 1,691 tickets sold

Step-by-step explanation:

1. Let's re-evaluate and organize our information given by the passage.

PRICE

Reg. tickets = $10 and $20

VIP​ seats = $30

Tickets sold (# of all tickets) = 3,237 tickets

Tickets sold OVERALL = 145 more​ $20 tickets sold than​ $10 tickets

Money made = ​$62,030

1. We need to represent x as the amount of the $10 tickets being sold, and y being the amount of $20 tickets being sold, so it'll look similarly like this:

x + y ( x + 145 ) = 3,237

Remember, the number of the $10 tickets and the number of $20 tickets being sold needs to equal 3,237.

2. Now, let's make estimates on what the # of tickets being for the $10 tickets is (because the # of $10 being sold affects the # of the $20 tickets being sold, and we have to start with this step first to in order find the number of $20 tickets sold).

3.

x = 1,000

y = 1,145

1,000 + 1,145= 2,145

NOT 1,000 (HIGHER THAN 1,000)

x = 2,000

y = 2,145

2,000 + 2,145 = 4,145

NOT 2,000 (LOWER THAN 2,000)

From these 2 estimates, the sales of x is between 1,000 and 2,000.

x = 1,546

y = 1,691

1,546 + 1,691 = 3,237 tickets

Q&A Education