Respuesta :
Answer:
The correct option is:
A. 470 mL
Explanation:
Molarity of the solution = 0.035M
[tex]Molarity=\frac{Number\:of\:moles}{Volume\:of\:solution\:in\:L}\\\\ Number\:of\:moles\:of\:Li_{3}PO_{4}=0.0164\\\\Volume\:of\:solution=\frac{number\:of\:moles}{Molarity}=\frac{0.0164}{0.035}=0.46857L=468.57mL[/tex]
It is approximately equal to 470 mL.
Hence, 470 mL of 0.035 M [tex]Li_{3}PO_{4}[/tex] solution contains 0.0164 moles of [tex]Li_{3}PO_{4}[/tex].
