Answer:
If we have 1600 offsprings than
YyLl = Tall plant with round pea seeds = 400 out of 1600
Yyll = Tall plant with wrinkled pea seeds = 400 out of 1600
yyLl = Dwarf plant with round pea seeds = 400 out of 1600 and
yyll = Dwarf plant with wrinkled pea seeds = 400 out of 1600
Explanation:
Taking an example of pea plant.
In this question each organism has heterozygous alleles i.e Yy of single character gene with having both dominant and recessive traits.
Say for example in this case capital "Y" represents Tall dominant character and small "y" represents dwarf recessive character. Similarly Capital "L" for example represents round dominant pea seeds and small "l" represents wrinkled recessive pea seeds.
In this question organism with having heterozygous characters (i.e having both dominant and recessive traits) are crossed. Underlined represents male part while non-underlined represents Female part of plant
YyLl × yyll-----------(1)
Four different types of gametes are produced from each organism due to meiosis in which chromosomes become half and alleles become separated.
i.e YL, Yl, yL and yl × yl, yl, yl and yl--------------(2)
Mating of these alleles are represented below in the form of checkerboard.
YL Yl yL yl
yl YyLl Yyll yyLl yyll
yl YyLl Yyll yyLl yyll
yl YyLl Yyll yyLl yyll
yl YyLl Yyll yyLl yyll
In this cross Phenotype of F1 generations are
YyLl = Tall plant with round pea seeds = 4 out of 16
Yyll = Tall plant with wrinkled pea seeds = 4 out of 16
yyLl = Dwarf plant with round pea seeds = 4 out of 16 and
yyll = Dwarf plant with wrinkled pea seeds = 4 out of 16
If we have 1600 offsprings than
YyLl = Tall plant with round pea seeds = 400 out of 1600
Yyll = Tall plant with wrinkled pea seeds = 400 out of 1600
yyLl = Dwarf plant with round pea seeds = 400 out of 1600 and
yyll = Dwarf plant with wrinkled pea seeds = 400 out of 1600
