Answer: 0.0930
Step-by-step explanation:
As per given , we have
H0: μcoffee = 6
Ha: μcoffee < 6
She finds z = −1.68 with one-sided P-value P = 0.0465.
The P-value for two-tailed test is calculated by :
[tex]2P(Z>|z|)[/tex]
For z= -1.68 , we have
[tex]2P(Z>|-1.68|)=2P(Z>1.68)[/tex]
[tex]=2(1-P(z\leq1.68))\ \ [\because\ P(Z>z)=1-P(Z\leq z)][/tex]
[tex]=2(1-0.9535213)\ \ \ [\text{ NORM.S.DIST(z, TRUE}]\\\\=2( 0.0464787)=0.0929573\approx0.0930[/tex]
Hence, the correct two-sided P-value for z = −1.68 is 0.0930 .