Kevin and Randy Muise have a jar containing 59 coins, all of which are either quarters or nickels. The total value of the coins in the jar is $11.15. How many of each type of coin do they have?

Question

contestada

Respuesta :

absor201 absor201 · Answer 1 · 2019-12-12T05:34:42+01:00

No. of quarter coins = 41

No. of nickle coins = 18

Step-by-step explanation:

Let x be the number of quarter coins and

y be the number of nickle coins

Then according to given statements

[tex]x+y = 59\ \ \ \ Eqn\ 1\\0.25x+0.05y = 11.15\ \ \ Eqn\ 2[/tex]

Multiplying equation 2 by 100 to get rid off decimals

[tex]25x+5y = 1115\ \ \ Eqn\ 3[/tex]

From eqn 1:

x = 59-y

Putting in equation 3

[tex]25(59-y)+5y = 1115\\1475-25y+5y = 1115\\1475-20y = 1115\\1475-1475-20y = 1115-1475\\-20y = -360[/tex]

Dividing both sides by -20

[tex]\frac{-20y}{-20} = \frac{-360}{-20}\\y = 18[/tex]

Putting y = 18 in equation 1

x+18 = 59

x = 59-18

x = 41

Hence,

No. of quarter coins = 41

No. of nickle coins = 18

Keywords: Simultaneous linear equations

Learn more about simultaneous linear equations at:

#LearnwithBrainly