Answer:
There are 6.024 grams of sodium hydroxide in the solution.
Explanation:
[tex]Molarity=\frac{Moles}{Volume (L)}[/tex]
[tex]Moles (n)=Molarity(M)\times Volume (L)[/tex]
Moles of sodium hydroxide = n
Volume of sodium hydroxide solution = 251.0 mL = 0.251 L
Molarity of the sodium hydroxide = 0.600 M
[tex]n=0.600 M\times 0.251 L=0.1506 mol[/tex]
Mass of 0.1506 moles of NaOH :
[tex]40 g/mol\times 0.1506 mol = 6.024 g[/tex]
There are 6.024 grams of sodium hydroxide in the solution.
