Answer:
She had baby sit for [tex]\frac{45}{12}[/tex] hrs OR 3 9/12 hrs OR 3 hours and 45 mins during the week.
Step-by-step explanation:
Given:
kelly babysits for 5 5/6 hours on the weekend.
5 5/6 can be rewritten as [tex]\frac{35}{6}[/tex]
This is 2 1/12 hours more than she babysits during the week.
2 1/12 hours can be rewritten as [tex]\frac{25}{12}[/tex]
Let the number of hours she works in week be x;
Hence the expression can be given as;
[tex]\frac{25}{12} + x = \frac{35}{6}[/tex]
Now Solving for x we get;
[tex]x = \frac{35}{6}-\frac{25}{12}[/tex]
Now making the denominator common we get;
[tex]x = \frac{35\times 2}{6\times2}-\frac{25}{12}[/tex]
[tex]x = \frac{70}{12}-\frac{25}{12}[/tex]
[tex]x = \frac{70-25}{12}[/tex]
[tex]x = \frac{45}{12}[/tex]
She had baby sit for [tex]\frac{45}{12}[/tex] hrs OR 3 9/12 hrs OR 3 hours and 45 mins during the week.
Answer:
During the week she babysits 3 3/4 hours
Step-by-step explanation:
Let's call x: the number of hours that she babysits during the week.
5 5/6 hours represents 2 1/12 hours more than she babysits during the week.
Therefore:
x + 2 1/12 = 5 5/6
x = 5 5/6 - 2 1/12
5 5/6 can be rewritten as (6*5 + 5)/6 = 35/6
2 1/12 can be rewritten as (12*2 +1)/12 = 25/12
Replacing:
x = 35/6 - 25/12
12 is multiple of both denominators, 6 and 12, then the subtraction will have 12 as denominator.
x = [35*(12/6) - 25*(12/12)]/12
x = (70 - 25)/12
x = 45/12 or 3 3/4
