Answer:
Arc(JH) = 0.44r
Step-by-step explanation:
In this question radius of the circle is not given.
Given information: Line segments J L and H K are diameters that intersect at center point M, m∠KML = 25°.
Using given information draw a diagram as shown below.
From the below figure it is clear that ∠KML and ∠JMH are vertically opposite angles.
If two lines intersect each other then vertically opposite angles are equal.
[tex]m\angle KML=n\angle JMH=25^{circ}[/tex]
Let the radius of the circle M is r.
The formula for arc length is
[tex]s=2\pi r(\frac{\theta}{360})[/tex]
where, r is radius of the circle and θ in degree.
[tex]Acr(JH)=2\pi r(\frac{25}{360})[/tex]
[tex]Acr(JH)=0.436332313r[/tex]
[tex]Acr(JH)\approx 0.44r[/tex]
Note: If the value of r is given, then substitute the value of r in the above equation and round to the nearest tenth of a centimeter.
Therefore, the length of arc (JH) is 0.44r.
