Answer:
zero, because the discriminant is negative
Step-by-step explanation:
The next question is missing : Which best describes how many real number solutions the equation has?
The quadratic equation gives:
[tex]x = \frac{-3 \pm \sqrt{-19}}{2} [/tex]
The discriminant is equal to -19. A negative discriminant means the quadratic formula has zero real solution.
The statement which best describes the number of real number solutions the equation has is zero, because the discriminant is negative.
In Mathematics, the standard form of a quadratic equation is given by;
ax² + bx + c = 0
Also, the quadratic formula is given by this mathematical equation:
[tex]x = \frac{-b\; \pm \;\sqrt{b^2 - 4ac}}{2a}[/tex]
Substituting the given parameters into the formula, we have;
[tex]x = \frac{-3\; \pm \;\sqrt{-19}}{2}[/tex]
Based on the simplest radical form, the number of real number solutions the equation has is zero, because the discriminant is negative.
Read more on quadratic equation here: brainly.com/question/1214333
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