The final temperature of the block is [tex]27.5^{\circ} C[/tex]
Explanation:
The amount of thermal energy Q supplied to a substance is related to the increase in temperature of the substance, [tex]\Delta T[/tex], according to the equation
[tex]Q=mC_s \Delta T[/tex]
where:
m is the mass of the substance
[tex]C_s[/tex] is the specific heat capacity of the substance
In this problem, we have:
m = 1.2 kg is the mass of the block
[tex]Q = 2,130 J[/tex] is the amount of energy supplied to the block
[tex]C_s = 710 J/kg^{\circ}C[/tex] is the specific heat capacity of the block
Solving for [tex]\Delta T[/tex], we find the increase in temperature:
[tex]\Delta T = \frac{Q}{m C_s}=\frac{2130}{(1.2)(710)}=2.5^{\circ}C[/tex]
And since the initial temperature was
[tex]T_i = 25^{\circ}C[/tex]
The final temperature will be
[tex]T_f = T_i + \Delta T = 25+2.5=27.5^{\circ} C[/tex]
Learn more about specific heat capacity:
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