Explanation:
d = Diameter of wheel = 27 cm
r = Radius = [tex]\frac{d}{2}=\frac{27}{2}=13.5\ cm[/tex]
m = Mass of wheel = 800 g
[tex]\omega_i[/tex] = Initial angular velocity = [tex]245\times \frac{2\pi}{60}\ rad/s[/tex]
Equation of rotational motion
[tex]\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{0-245\times \frac{2\pi}{60}}{50}\\\Rightarrow \alpha=-0.51312\ rad/s^2[/tex]
Moment of inertia is given by
[tex]M=\frac{1}{2}mr^2\\\Rightarrow M=\frac{1}{2}\times 0.8\times 0.135^2\\\Rightarrow M=0.00729\ kgm^2[/tex]
Torque is given by
[tex]\tau=I\alpha\\\Rightarrow \tau=0.00729\times -0.51312\\\Rightarrow \tau=-0.0037406448\ Nm[/tex]
The torque the friction exerts is -0.0037406448 Nm
For more information on torque and moment of inertia refer
https://brainly.com/question/13936874
https://brainly.com/question/3406242
