Answer:
"the summation from n equals one to 6 of quantity negative 7 minus 3 times n"
Step-by-step explanation:
General term of an arithmetic sequence:
[tex]a_n=a_1+(n-1)r[/tex]
Where
[tex]a_1[/tex] is the first term
n is the number of terms
r is the common difference
The value of r can be found by subtracting two consecutive values
[tex]r=a_2-a_1=-13+10=-3[/tex]
Then
[tex]a_n=-10+(n-1)(-3)=-7-3n[/tex]
If we want to sum the first six terms of the sequence, we must find
[tex]\sum_{n=1}^{n=6}(-7-3n)[/tex]
The correct option is
"the summation from n equals one to 6 of quantity negative 7 minus 3 times n"
