Answer:
Zero %
Explanation:
Male is BBCc and Female is bbcc , then
BBCc x bbCc will always give the B allele in all the F1 generation combinations. That is, all individuals will be coloured, although a half can be straight coat.
If you use a Punnett square, it will be easy to visualize the cross
For the white curly coat, the percent chance of offspring would be - zero percent.
In the given case there is a dihybrid cross as it is a cross between two individuals who differ in two observed traits that are controlled by two distinct genes.
It is cross between h-m-zygous dominant for color (BB) and heterozygous curly for a coat (Cc) which constitutes it genotype - BBCc and h-m-zygous white for color (bb) and hmzygous for a straight coat (cc) which constitutes - bbcc.
Cross - BBCc X bbcc
gametes - BC, Bc and bc
Punnett square:
BC Bc
bc BbCc Bbcc
bc BbCc Bbcc
we get color curly and color straight coat on 50% chances each.
For the white curly coat, the percent chance of offspring would be - zero percent as one should have bbCc or bbCC.
Learn more about dihybrid cross:
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